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Find an approximation of (0. 99)^5 using...

Find an approximation of `(0. 99)^5` using the first three terms of its expansion.

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`therefore (0.99)^{5} =(1-0.01)^{5} `
`=5_{C_0}(1)^{5}-5_{C_1}(1)^{4}(0.01)+5_{C_2}(1)^{3}(0.01)^{2} `
`=1-5(0.01)+10(0.01)^{2} `
`=1-0.05+0.001 `
`=1.001-0.05 `
`=0.951` ...
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