Find the 10th term in the binomial expansion of `(2x^2+1/x)^(12)dot`

Explanation

We know that, the `(r+1)^{ {th }}` term in the expansion of `(a+b)^{n}` is


t_{r+1}=\ ^{n} C_{r} a^{n-r} b^{r}


Here `a=2 x^{2}, b=frac{1}{x}, n=12` and for `t_{10}, r=9`


`therefore` tenth term in the expansion of `(2 x^{2}+frac{1}{x})^{12}`


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