Find the constant term in the expansion of `((4x^2)/3+3/(2x))^9`.

Explanation

To find the constant term in the expansion of \(\left(\frac{4x^2}{3} + \frac{3}{2x}\right)^9\), we will use the Binomial Theorem. The Binomial Theorem states that:

\[ (a + b)^n = \sum_{r=0}^{n} \binom{n}{r} a^{n-r} b^r \]

In our case, \(a = \frac{4x^2}{3}\), \(b = \frac{3}{2x}\), and \(n = 9\).

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