Show that the middle term in the expansion of `(1+x)^(2n)\ ` is `=frac{1.3 cdot 5 ldots(2 n-1)}{n !} 2^{n} x^{n}`

Explanation

In the expansion of `(1+x)^{2 n}` in total `2 n+1` terms are present.


So, middle term will be,


`frac{(2 n+1)+1}{2}=frac{2 n+2}{2} `


={n}+1


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