Find the coefficient of `x^(10)` in the binomial expansion of `(2x^2-1/x)^(20),\ w h e n\ x!=0.`

Explanation

Here,


`T_{r+1}=\ ^{20} C_{r}(2 x^{2})^{20-r}(frac{-1}{x})^{r} `


`=(-1)^{r 20} C_{r}(2^{20-r})(x^{40-2 r-r})`


For this term to contain `x^{10}`, we must have:


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