Based on the data given for half cell
`(M^(x+n)+ , M^(x+) || Pt`
% of reduced form 50 20
Potential (V) 0.1, 0.112
the value of n is:

The half cell potentials of a halfcell A^((x+n)+) , A^(x+)|pt were found to be as follows : {:(% "of reduced form",24.4,48.8),("Half cell potential (V)",0.101,0.115):} Determinwe the value of n .

The half cell potentials of a halfcell A^((x+n)+) , A^(x+)|pt were found to be as follows : {:(% "of reduced form",24.4,48.8),("Half cell potential (V)",0.101,0.115):} Determinwe the value of n .

The half cell potential of a half-cell A^(x+), A^((x+n)+)|Pt were found to be as follows: {:(%"of reduced form",24.4,48.8),("Cell potential"//N,0.101,0.115):} Determine the value of n . [take (2.303RT)/(F) = 0.05, log_(10)24.4 = 1.387, log_(10) 75.6 = 1.878 log_(10) 48.8 = 1.688, log_(10) 51.2 = 1.709]

The half cell potential of a half-cell A^(x+), A^((x+n)+)|Pt were found to be as follows: {:(%"of reduced form",24.4,48.8),("Cell potential"//N,0.101,0.115):} Determine the value of n . [take (2.303RT)/(F) = 0.05, log_(10)24.4 = 1.387, log_(10) 75.6 = 1.878 log_(10) 48.8 = 1.688, log_(10) 51.2 = 1.709]

The half cell potential of a half-cell A^(x+), A^((x+n)+)|Pt were found to be as follows: {:(%"of reduced form",24.4,48.8),("Cell potential"//N,0.101,0.115):} Determine the value of n . [take (2.303RT)/(F) = 0.05, log_(10)24.4 = 1.387, log_(10) 75.6 = 1.878 log_(10) 48.8 = 1.688, log_(10) 51.2 = 1.709]

The EMF of the cell M|M^(n+) (0.02 M) | H^(+) (1 M) | H_(2)(g) (1 atm), Pt at 25^(@) C is 0.81 V. Calculate the valency of the metal if the standard oxidation potential of the metal is 0.76 V

The quadratic equation x^2+m x+n=0 has roots which are twice those of x^2+p x+m=0a dm ,na n dp!=0. The n the value of n//p is _____.

For the half - cell Fe^(3+), Fe^(2+)|Pt , the concentration of Fe^(2+) and Fe^(3+) ions are 0.1 and 0.01 (M) respectively. Determine the reduction potential of the half - cell at 25^(@)C . Given : E_(Fe^(3+), Fe^(2+)|Pt)^(@)=+0.77V