Find the 7th term in the expansion of `((4x)/5+5/(2x))^8dot`

Explanation

To find the 7th term in the expansion of \(\left(\frac{4x}{5} + \frac{5}{2x}\right)^8\), we will use the Binomial Theorem. The general term in the expansion is given by:

\[ T_{r+1} = \binom{n}{r} a^{n-r} b^r \]

where \(n\) is the exponent, \(a\) is the first term, \(b\) is the second term, and \(r\) is the term index starting from 0.

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