Find the 7th term from the end in the expansion of `(2x^2-3/(2x))^8dot`

Explanation

To find the 7th term from the end in the expansion of \((2x^2 - \frac{3}{2x})^8\), we will follow these steps:

### Step 1: Identify the values of \(n\) and \(k\)
In the binomial expansion of \((a + b)^n\), the general term \(T_{r+1}\) is given by:
\[ T_{r+1} = \binom{n}{r} a^{n-r} b^r \]
Here, \(n = 8\), \(a = 2x^2\), and \(b = -\frac{3}{2x}\).
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