Find the coefficient of `x` in the expansion of `(1-3x+7x^2)(1-x)^(16)`.

Explanation

To find the coefficient of \( x \) in the expansion of \( (1 - 3x + 7x^2)(1 - x)^{16} \), we will follow these steps:

### Step 1: Expand \( (1 - x)^{16} \) using the Binomial Theorem
According to the Binomial Theorem, we can expand \( (1 - x)^{16} \) as follows:

\[ (1 - x)^{16} = \sum_{k=0}^{16} \binom{16}{k} (-x)^k = \sum_{k=0}^{16} \binom{16}{k} (-1)^k x^k \]
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