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Find the middle term in the expansion o...

Find the middle term in the expansion of `(2x^2-1/x)^7`

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`(2x^2-1/x)^7`
Middle terms are
`T_4`=`T_(3+1)`and`T_5`=`T_(4+1)`
`T_(4+1)`=`7_(C_4)``(2x^2)^(7-4)``(-1/x)`
`(7*6*5)/(1.2.3)``(2x^2)^3``1/x^4`
`35*8*x^6/x^4`=`280x^2`
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