Calculate the `EMF` of a Daniel cell when the concentartion of `ZnSO_(4)` and `CuSO_(4)` are `0.001M` and `0.1M` respectively. The standard potential of the cell is `1.1V`.

The standard electrode potential of Zn^(2+)|ZnandCu^(2+)|Cu are - 0.76 and 0.34 V respectively . The standard e.m.f. of the cell is :

The e.m.f. of the cell obtained by combining Zn and Cu electrode of a Daniel cell with N calomel electrode in two different arrangements are 1.083V and 0.018V respectively at 25^(@)C . If the standard reduction potential of N calomel electrode is 0.28V find the emf of Daniel cell.

The e.m.f. of the cell obtained by combining Zn and Cu electrode of a Daniel cell with N calomel electrode in two different arrangements are 1.083V and 0.018V respectively at 25^(@)C . If the standard reduction potential of N calomel electrode is 0.28V find the emf og Daniel cell.

In the electrochemical cell: Zn|ZnSO_(4)(0.01 M)||CuSO_(4)(1.0M)|Cu The EMF of this Daniel cell is E_(1) . When the concentration of ZnSO_(4) is changed to 1.0(M) and that of CuSO_(4) changed to 0.01(M), the EMF changes to E_(2) . From the following which one is the relationship between E_(1) and E_(2)" "("Given, "(RT)/(F)=0.059) -