Find the middle term in the expansion of : `(1-2x+x^2)^n`

Explanation

Given expression `(1−2x+x^ 2)^ n`

⇒ `(1−2x+x ^2 )^n` =`[(1−x)^2]^n` =`(1−x)^(2n)`

Middle term `((2n)/2​+1)^(th) ⇒(n+1)^(th)` term

`T_( n+1)`​ =`2n_(C1)​(1)^ (2n−n)(−x)^n`

= `(2n!)/(n!)^2​(1)^n(−x)^n`
Middle term is `(2n!)/(n!)^2(−1)^nx^n`