The middle term of `(x-1/x)^(2n+1)` is

Explanation

Given
`(x-frac{1}{x})^{2 n+1}`


Here, `(2 n+1)` is an odd number.


Therefore, the middle terms are `(frac{2 n+1+1}{2})` th and `(frac{2 n+1+1}{2}+1)` th `i .` e `(n+1)` th and `(n+2)` th terms .


Now, we have:
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