Find the term independent of `x` in the expansion of `[(3x^2/2)-(1/3x)]^9`

Explanation

Given


` (frac{3}{2} x^{2}-frac{1}{3 x})^{9} `


`T_{r+1}=\ ^{9} C_{r}(frac{3}{2} x^{2})^{9-r}(frac{-1}{3 x})^{r} `


`=(-1)^{r} 9 C_{r cdot} frac{3^{9-2 r}}{2^{9-r}} times x^{18-2 r-r}`


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