In the expansion of `(1+x)^n` the binomial coefficients of three consecutive terms are respectively 220, 495 and 792 find the value of `n`.

Explanation

To solve the problem, we need to find the value of \( n \) in the expansion of \( (1+x)^n \) given that the binomial coefficients of three consecutive terms are 220, 495, and 792.

### Step-by-Step Solution:

1. **Identify the Binomial Coefficients**:
Let the three consecutive terms be represented as:
\[
\binom{n}{r-1} = 220, \quad \binom{n}{r} = 495, \quad \binom{n}{r+1} = 792
...