If in the expansion of `(1+x)^n` the coefficient of three consecutive terms are 56,70 and 56, then find `n` and the position of the terms of these coefficients.

Explanation

To solve the problem, we need to find the value of \( n \) and the positions of the terms in the expansion of \( (1 + x)^n \) where the coefficients of three consecutive terms are given as 56, 70, and 56.

### Step 1: Define the terms
Let the three consecutive terms be:
- Coefficient of the \( r \)-th term: \( T_r = \binom{n}{r} \)
- Coefficient of the \( (r + 1) \)-th term: \( T_{r+1} = \binom{n}{r + 1} \)
- Coefficient of the \( (r + 2) \)-th term: \( T_{r+2} = \binom{n}{r + 2} \)

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