If `p` is a real number and if the middle term in the expansion of `(p/2+2)^8` is 1120, find `p`

Explanation

In the binomial expansion of `(frac{p}{2}+2)^{8}`, we observe that `(frac{8}{2}+1)^{ {th }}` i.e., `5^{ {th }}` term is the middle term.
It is given that the middle term is 1120 .


`therefore T_{5}=1120 `


`Rightarrow \ ^{8} C_{4}(frac{p}{2})^{8-4}(2)^{4}=1120 `


`Rightarrow p^{4}=16 `


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