Which term is independent of `x ` in the expansion of `(x-1/(3x^2))^9?`

Explanation

To find the term independent of \( x \) in the expansion of \( \left( x - \frac{1}{3x^2} \right)^9 \), we can follow these steps:

### Step 1: Write the General Term
The general term \( T_{r+1} \) in the binomial expansion of \( (a + b)^n \) is given by:
\[ T_{r+1} = \binom{n}{r} a^{n-r} b^r \]
In our case, \( a = x \), \( b = -\frac{1}{3x^2} \), and \( n = 9 \). Thus, the general term becomes:
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