In the expansion of `(x^2-1/(3x))^9` the term without `x` is equal to a. `(28)/(81)` b. `(-8)/(243)` c. `(28)/(243)` d. none of these

Explanation

To find the term without \( x \) in the expansion of \( (x^2 - \frac{1}{3x})^9 \), we can follow these steps:

### Step 1: Identify the general term in the binomial expansion
The general term \( T_r \) in the expansion of \( (a + b)^n \) is given by:
\[ T_r = \binom{n}{r} a^{n-r} b^r \]
In our case, \( a = x^2 \), \( b = -\frac{1}{3x} \), and \( n = 9 \). Thus, the general term becomes:
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