Home
Class 12
CHEMISTRY
E(cell)^(@) for the reaction MnO(4)^(-)+...

`E_(cell)^(@)` for the reaction `MnO_(4)^(-)+5Fe^(+2)+8H^(+)rarrMn^(+2)+5Fe^(+)+4H_(2)O` is 0.59 V at 298 K Find the equilibriuym constant

Promotional Banner

Similar Questions

Explore conceptually related problems

E_(cell)^(@) for the reaction MnO_(4)^(-)+5Fe^(+2)+8H^(+)rarrMn^(+2)+5Fe^(+3)+4H_(2)O is 0.59 V at 298 K. Find the equilibrium constant

The E_("cell") of the reaction MnO_(4)^(-)+Fe^(+2)+H^(+)rarrMn^(+)+H_(2)O is 0.59 V at 25^(@)C The equilibrium constant for the reaction is

The E_("cell") of the reaction MnO_(4)^(-)+Fe^(+2)+H^(+)rarrMn^(2+)+H_(2)O is 0.59 V at 25^(@)C The equilibrium constant for the reaction is

MnO_(4)^(-)+8H^(+)+n e^(-)rarrMn^(2+)+4H_(2)O The value of n is

KMnO_(4) reacts with ferrous ammonium sulphate according to the equation MnO_(4)^(-)+5Fe^(2+)+8H^(+) rarr Mn^(2+)+5Fe^(3+)+4H_(2)O , here 10 ml of 0.1 M KMnO_(4) is equivalent to

Balance the equation MnO_4^- +H^+ +Fe^2 rarr Mn^2 + H_2O + Fe^3^+

Assertion: In the reaction, MnO_(4)^(-)+5Fe^(2+)+8H+ rarr Mn^(2+)+5Fe^(3+)+4H_(2)O , MnO_(4)^(-) acts as oxidising agent. Reason: In the above reaction, n - factor is 5 .