If `T_2/T_3` in the expansion of `(a + b)^n and T_3/T_4` in the expansion of `(a + b)^(n+3)` are equal, then n is equal to

Explanation

In the expansion `(a+b)^{n}`, we have


`frac{T_{2}}{T_{3}}=frac{\ ^{n} C_{1} a^{n-1} times b^{1}}{\ ^{n} C_{2} a^{n-2} times b^{2}}`


In the expansion `(a+b)^{n+3}`, we have


`frac{T_{3}}{T_{4}}=frac{\ ^{n+3} C_{2} a^{n+1} b^{2}}{\ ^{n+3} C_{3} a^{n} b^{3}}`


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