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Two ships are sailing in the sea on the either side of the lighthouse.The angles of depression of two ships as observed from the top of the lighthouse are `60^@` and `45^@`, respectively. If the distance between the ships is `100((sqrt3+1)/sqrt3)` m, then find the height of the lighthouse

Text Solution

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`In/_CDB`
`tan45^@=(CD)/(DB)`
`1=h/x`
`h=x`
`In/_ACD`
`tan60^@=(CD)/(AD)`
`sqrt3=h/((100(sqrt3+1)/sqrt3)-h)`
`100(sqrt3+1)-hsqrt3=h`
...
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