If `t_n` denotes the nth term of the series `2+3+6+11+18+...t h e nt_(50)` a.`49^2-1` b. `49^2` c. `50^2+1` d. `49^2+2`

Explanation

We have given series as `2+3+6+11+18+.....`

Here,

First term, `a=2`

The formula for n^th term is given by,

`t_n=a+(n-1)^2`

Then,

`t_{50}=2+(49 )^2`

Hence correct option is (d).