By using the concept of slope, show that the points (-2,-1), (4,0), (3,3) and (-3,2) are the vertices of a parallelogram.

Explanation

Let `A(-2,-1)`,` B(4,0)`, `C(3,3)` and `D(-3,2) `be the given points

Now,

slope of A B=`frac[0+1][4+2]=frac[1]6`

Slope of B C=`frac[3-0][3-4]=-3`

Slope of C D=`frac[2-3][-3-3]=frac[1]6`

Slope of D A=`frac[-1-2][-2+3]=-3`

Clearly, we have,

Slope of A B= Slope of C D

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