Find the equation of the straight line passing through (3,-2) and making an angle of `60^0` with the positive direction of y-axis.

Explanation

Given points `(3,-2) equiv(x_{1}, y_{1})`

The angle made by line with `y` axis is `60^{circ}`

The angle made by line with `x` axis is `90-60^{circ}=30^{circ}`

The slope of line is m=`tan 30^{circ}`=`frac{1}{sqrt{3}}`

Equation of line is given as,

`Rightarrow y-y_1`=`m(x-x_1)`

`Rightarrow y+2`=`frac{1}{sqrt{3}}(x-3)`

`Rightarrow sqrt{3}(y+2)`=`x-3`

...