Find the equation of the side BC of the triangle ABC whose vertices are `A(-1,-2),\ B(0,1)a n d C(2,0)` respectivley. Also, find the equation of the median through `A(-1,\ -2)dot`

Explanation

The equation of `BC`

`y-1=frac{0-1}{2-0}(x-0)`

`x+2y-2=0`

Let `D` be the mid-point of `BC`.

`:. D=(frac{0+2}{2}, frac{1+0}{2})`

So the equaton of median `AD` is `y+2=frac{frac{1}{2}+2}{1+1}(x+1)`

`5x-4y-3=0`