Find the equation to the straight line which passes through the point (5,6) and has intercepts on the axes. i)equal in magnitude and both postive ii)equal in magnitude but opposite in sign

Explanation

The equation of line in intercept form is `\frac{x}{a}+\frac{y}{b}=1`

`(i) a=b` and line passes through `(5,6)`

Therefore, equation of line becomes ` x+y=a`

`\implies 5+6=a`

`\implies a=11`

Hence, the required equation is, `x+y=11`

`(ii) a=-b` and line passes through `(5,6)`

Therefore, equation of line becomes ` x-y=a`

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