Find the distance of point (2,3) from the line `2x-3y+9=0` measured along a line making an angle of `45^0` with the x-axis.

Explanation

To find the distance of the point (2, 3) from the line \(2x - 3y + 9 = 0\) measured along a line making an angle of \(45^\circ\) with the x-axis, we can follow these steps:

### Step 1: Find the slope of the line making a \(45^\circ\) angle with the x-axis.
The slope \(m\) of a line making an angle \(\theta\) with the x-axis is given by \(m = \tan(\theta)\). For \(\theta = 45^\circ\):
\[ m = \tan(45^\circ) = 1 \]

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