Find the distance of the point (2,5) from the line `3x+y+4=0` measured parallel to the line `3x-4y+8=0`

Explanation

To find the distance of the point (2, 5) from the line \(3x + y + 4 = 0\) measured parallel to the line \(3x - 4y + 8 = 0\), we will follow these steps:

### Step 1: Find the slope of the line \(3x - 4y + 8 = 0\)
First, we need to rewrite the line in slope-intercept form \(y = mx + b\):
\[ 3x - 4y + 8 = 0 \implies -4y = -3x - 8 \implies y = \frac{3}{4}x + 2 \]
The slope \(m_1\) of this line is \(\frac{3}{4}\).
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