Reduce the equation `sqrt(3)x+y+2=0` to: Slope intercept form and find slope and y-intercept. Intercept form and find intercept on the axes The normal form and find `p\ a n d\ alpha`

Explanation

`sqrt3x+y+4=0`

`implies sqrt3x+y=-4`

`implies -sqrt3/2x-y/2=2`

`implies xcos (frac{7pi}{6})+y sin (frac{7pi}{6})=2`

Thus, `p=2` and `alpha=frac{7pi}{6}`