The mass of proton is `1.0073 u` and that of neutron is `1.0087 u` (`u=` atomic mass unit). The binding energy of `._(2)He^(4)` is (mass of helium nucleus `=4.0015 u`)

The mass of proton is 1.0073 u and that of neutron is 1.0087 u ( u= atomic mass unit). The binding energy of .2He^(4) is (mass of helium nucleus =4.0015 u )

The mass of proton is 1.0073 u and that of neutron is 1.0087 u ( u=atomic mass unit ). The binding energy of ._2^4He , if mass of ._2^4He is 4.0015 u is

The mass of proton is 1.0073 u and that of neutron is 1.0087 u ( u=atomic mass unit ). The binding energy of ._2^4He , if mass of ._2^4He is 4.0015 u is

If the mass of proton= 1.008 a.m.u. and mass of neutron=1.009a.m.u. then binding energy per nucleon for ._(4)Be^9 (mass=9.012 amu) would be-

The atomic mass . _2^4He is 4.0026 u and the atomic mass of ._1^1H is 1.0078 u . Using atomic mass units instead of kilograms, obtain the binding energy of ._2^4He nucleus.

The atomic mass . _2^4He is 4.0026 u and the atomic mass of ._1^1H is 1.0078 u . Using atomic mass units instead of kilograms, obtain the binding energy of ._2^4He nucleus.

The mass of a proton is 1.00816 u and that of a neutron is 1.00902 u. If the mass of a deuterium nucleus (._1H^2) is 2.01479 u, then what will be the binding energy of this nucleus ? (1 u = 931.2 MeV)

Mass of Helium nucleus = 4 . 00015 amu and mass of a proton =1 .0073 amu mass of neutron= 1.0087 amu Calculate the mass defect and energy liberated in formation of He nucleus and also evaluate binding energy of ._(2)He^(4) nucleus.

The atomic mass of F^(19) is 18.9984 m_(u) . If the masses of proton and neutron are 1.0078 m_(u) and .0087 m_(u) . Respectively, calculate the binding energy per nucleon (ignore the mass of electrons). (1 m_(u) = 931) MeV)