Find the values of ` theta ` and p, if the equation `xcostheta+ysintheta=p` is the normal form of the line `sqrt(3)x+y+2=0` .

Explanation

`sqrt3x+y+2=0`

`implies sqrt3x+y=-2`

`implies -sqrt3/2x-y/2=1`

`implies xcos (frac{7pi}{6})+y sin (frac{7pi}{6})=1`

Thus, `p=1` and `theta=frac{7pi}{6}`