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The perpendicular distance of a line fro...

The perpendicular distance of a line from the origin is 5 units and its slope is -1. Find the equation of the line.

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Equation of a line in slope-intercept form is,
`y=mx+c`
Given, the slope `=−1`
`implies y=−x+c`
`implies x+y−c=0`
Its perpendicular distance from origin `=5` units.
We know that the perpendicular distance of point ` (x_1,y_1)` from line `ax+by+c=0` is,
`=|frac{ax_1+by_1+c}{sqrt{a^2+b^2}}|`
...
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