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Find the area of the triangle formed by the lines `y = x, y= 2x, y=3x+4`

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For intersection point of lines y = x and y = 2x,
We have 2x = x ⇒ 2x - x = 0 ⇒ x = 0
Put x = 0 in line y = x, we get y = 0.
Hence, intersection point of lines y = x and y = 2x is B(0, 0)
. For intersection point of lines y = x and y = 3x + 4,
We have x = 3x + 4 ⇒ 2x = -4 ⇒ x = -2
Put x = -2 in line y = x, we get y = -2.
Hence, intersection point of lines y = x and y = 3x + 4 is A(-2, -2).
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