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Find the point of intersection of the following pairs of lines: `b x+a y=a b\ a n d\ b x+b y=a bdot`

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Given: The equations of the lines are as follows: bx + ay − ab = 0… (1)
ax + by = ab ⇒ ax + by − ab = 0 … (2)
Let us find the point of intersection of pair of lines.
By solving (1) and (2) using cross – multiplication method, we get
`=x/(-a^2b+ab^2)=y/(-a^2b+ab^2)=1/(b^2-a^2)`
`x=(ab)/(b+a ) and y=(ab)/(b+a)`
∴ The point of intersection is (ab/a + b, ab/a + b)
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