Find the area of triangle formed by the lines :`\ x+y-6=0,\ x-3y-2=0\ a n d\ 5x-3y+2=0`

Explanation

The given equations are x + y = 6 …(i)

x – 3y = 2 …(ii)

and 5x – 3y + 2 = 0 or 5x – 3y = -2 …(iii)

Let eq. (i), (ii) and (iii) represents the sides AB, BC and AC respectively of ΔABC

Firstly, we solve the equation (i) and (ii)

x + y = 6 …(i)

x – 3y = 2 …(ii)


Subtracting eq. (ii) from (i), we get

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