Prove that the lines `sqrt(3)x+y=0,\ sqrt(3)y+x=0,\ sqrt(3)x+y=1\ a n d\ sqrt(3)y+x=1` form a rhombus.

Explanation

Given,`3 x+y=0 ` ...(i)


`√3 y+x=0 ` ...(ii)


`√3 x+y=1 ...(iii)`


`√3 y+x=1 ...(iv)`


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