Find equation of the line perpendicular to the line `x-7y +5=0` and having x intercept 3.

Explanation

The equation of a line perpendicular to `x−7y+5=0` is


`7x+y+λ=0`


Its x-intercept is` 3`. This means that the line cuts x-axis at a distance of `3` units from the origin.


Consequently, it passes through the point `(3,0)` on x-axis.

Therefore, `21+0+λ=0`
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