The equations of two sides of a triangle are `3x-2y+6=0\ a n d\ 4x+5y-20\ a n d\ ` the orthocentre is (1,1). Find the equation of the third side.

Explanation

To find the equation of the third side of the triangle given the equations of two sides and the orthocenter, we can follow these steps:

### Step 1: Identify the equations of the given sides
The equations of the two sides of the triangle are:
1. \( AB: 3x - 2y + 6 = 0 \)
2. \( AC: 4x + 5y - 20 = 0 \)

### Step 2: Convert the equations to slope-intercept form
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