find the equation of a line passing through (3,-2)and perpendicular to the line `x-3y+5=0`

Explanation

The equation is perpendicular to `x – 3y + 5 = 0 `and passes through `(3,-2)`


The equation of the line perpendicular to `x − 3y + 5 = 0` is` 3x + y + λ = 0,`


Where, λ is a constant. It passes through `(3, − 2)`.


Substitute the values in above equation, we get

`3 (3) + (-2) + λ = 0 9 – 2 + λ = 0 `

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