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Find the equation of a line drawn perpen...

Find the equation of a line drawn perpendicular to the line `x/4+y/6 = 1` through the point where it meets the `y` axis.

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The equation of the given line is `x/4 + y/6 =1.`
This equation can also be written as `3x + 2y – 12 = 0 `
`y= -3/2x +6,`which is of the form `y = mx + c`
Slope of the` = - 3/2` given line
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RD SHARMA-THE STRAIGHT LINES -Solved Examples And Exercises
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  2. Prove that the lines 2x-3y+1=0,\ x+y=3,\ 2x-3y=2\ a n d\ x+y=4 form a ...

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  4. The perpendicular from the origin to the line y=m x+c meets it at the ...

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  8. Find the coordinates of the foot o the perpendicular from the point ...

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  9. Find the projection of the point (1,0) on the line joining the points ...

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  10. Find the equation of a line perpendicular to the line 3x+y+5=0 and at ...

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  11. The line 2x+3y=12 meets the x-axis at A and y-axis at B. The line thro...

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  12. Find the equation of the straight line which cuts off intercept on ...

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  13. The equations of the perpendicular bisectors of the sides A Ba n dA C ...

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  14. Find the angles between the pairs of straight lines: x+sqrt(3)y-5=0\ a...

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  15. Find the angles between the pairs of straight lines: y=(2-sqrt(3))x+5\...

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  16. Find the obtuse angle between the lines x-2y+3=0\ a n d\ 3x+y-1=0.

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  17. A line passing through the points (a ,\ 2a) and (-2,\ 3) is perpendicu...

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  18. The hypotenuse of a right angled triangle has its ends at the points...

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  19. Find the angles between each of the following pairs of straight line: ...

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