Find the coordinates of the foot o the perpendicular from the point (-1, 3) to the line `3x-4y-16=0`

Explanation

Let (a,b) be the coordinates of the foot of the perpendicular from the point `(−1,3)` to the line `3x−4y−16=0`

Slope of the line joining` (−1,3)` and` (a,b)`, is
`m_1​=(b−3​)/(a+1)`

Slope of the line `3x−4y−16=0` or` y=3/4​x−4,m_2​=3/4`​

Since these two lines are perpendicular,`m1​m2​=−1`

`(b−3​)/(a+1)⋅{3/4​}=−1`

`=>(3b−9)/(4a+4)​=−1`

`=>3b−9=4a−4`

`=>4a+3b=5...(1)`

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