Find the angles between each of the following pairs of straight line: `x-4y=3\ a n d\ 6x-y=11.`

Explanation

Given pairs of straight lines are
`x−4y=3` and `6x−y=11`

`tantheta`=
​​=`(m_2​−m_1​​)/(1+m_2​m_1​)`

Slopes are `m_1​=1/4`​ and `m_2​=6`

Therefore, `tantheta=(​6−1/4​​)/(1+6/4)=(23)/(10)`

`⇒theta=tan^(−1)((23)/(10)​)`
is the angle between pair of straight lines.