Find the perpendicular distance from the origin of the perpendicular from the point (1,2) upon the straight line `x-3y+4=0.`

Explanation

`x−3
​y+4=0`


Perpendicular distance is =` (
​ax+by+c​)/sqrt(a^2+b^2)`

Given point is `(1,2)`

Therefore perpendicular distance, `d=(1×1−sqrt(3)
​×2+4​)/sqrt(1^2+sqrt(3)^2)`

...