Find the distance of the point (1,2) from the straight line with slope 5 and passing through the point of intersection of `x+2y=5\ a n d\ x-3y=7.`

Explanation

Given lines` x+2y=5 `and `x−3y=7` intersect at `(29/5​,−2/5​)`.


The equation of the slope 5 passing through this point is


`y+2/5​=5(x−29/5​)` or , `25x−5y−147=0`


The distance d of the point (1,2) from this line is


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