What are the points on the yaxis whose distance from the line `x/3+y/4=1`is 4 units.

Explanation

Let (0,b) be the point on the y-axis whose distance from line 3x​+4y​=1 is 4 units.

The given line can be written as 4x+3y−12=0....(1)

Thus using distance formula,

`4=(​4(0)+3(b)−12∣)/sqrt(4^2+3^2)`

`=>``4=(3b−12)/5`
​
`=>``20=(3b−12)`

`=>20=pm(3b−12)`

`=>`20=(3b−12) or `20=−{3b−12}`

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