Find the distance between the parallel lines `3x-4y+9=0\ a n d\ 6x-8y-15=0.`

Explanation

To find the distance between the parallel lines \(3x - 4y + 9 = 0\) and \(6x - 8y - 15 = 0\), we will follow these steps:

### Step 1: Confirm that the lines are parallel
To check if the lines are parallel, we need to compare their slopes. The general form of a line is given by \(Ax + By + C = 0\). The slope of the line is given by \(-\frac{A}{B}\).

For the first line \(3x - 4y + 9 = 0\):
- Here, \(A_1 = 3\) and \(B_1 = -4\).
- The slope \(m_1 = -\frac{3}{-4} = \frac{3}{4}\).
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