One diagonal of a square is along the line `8x-15 y=0` and one of its vertex is (1, 2). Then the equations of the sides of the square passing through this vertex are `23 x+7y=9,7x+23 y=53` `23 x-7y+9=0,7x+23 y+53=0` `23 x-7y-9=0,7x+23 y-53=0` none of these

Explanation

Let BD be the diagonal `8x−15y=0 `of square ABCD


Let slope of AB be m and slope of BD is` 8/15` then,


`tan 45^∘=(m−8/15)/(1+8/15 m)`


`15−8m=15m−8`


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