Show that the point (3,-5) lies between the parallel lines `2x+3y-7=0\ a n d\ 2x=3y+12=0` and find the equation of lines through (3,-5) cutting the above lines at an angle of `45^@` .

Explanation

The distance from (3, -5) to the line


`2x+3y−7=0
`

`∣(ax_1+by_1+c)/sqrt(a^2+b^2)|`


=`∣(2(3)+3(−5)−7)/sqrt((2)^2+(3)^2)∣
`

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