Find the equation of a straight line passing through the point of intersection of `x+2y+3=0\ a n d\ 3x+4y+7=0` and perpendicular to the straight line `x-y+8=0.`

Explanation

To find the equation of a straight line passing through the point of intersection of the lines \(x + 2y + 3 = 0\) and \(3x + 4y + 7 = 0\), and perpendicular to the line \(x - y + 8 = 0\), we can follow these steps:

### Step 1: Find the point of intersection of the two lines
We have the equations:
1. \(x + 2y + 3 = 0\) (Equation 1)
2. \(3x + 4y + 7 = 0\) (Equation 2)

To find the point of intersection, we can solve these equations simultaneously.
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